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5x^2+120x-1008=0
a = 5; b = 120; c = -1008;
Δ = b2-4ac
Δ = 1202-4·5·(-1008)
Δ = 34560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{34560}=\sqrt{2304*15}=\sqrt{2304}*\sqrt{15}=48\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-48\sqrt{15}}{2*5}=\frac{-120-48\sqrt{15}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+48\sqrt{15}}{2*5}=\frac{-120+48\sqrt{15}}{10} $
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